Math, asked by Anonymous, 9 months ago

Evaluate ∫ 3ax/(b2 +c2x2) dx​

Answers

Answered by SwaggerGabru
15

Step-by-step explanation:

HOPE THE ATTACHMENT HELPS YOU

Attachments:
Answered by tiwariakdi
0

At last we get the value of ∫ 3ax/(b^2 +c^2x^2) dx  which is  (3a/c) ln|b^2 + c^2x^2| + C.

Integration is a technique for combining or merging the parts to get at the total.

Sign of integration is ∫dx.

The main applications of integration are computing the volumes of three-dimensional objects and determining the areas of two-dimensional regions.

To evaluate the given integral,

u = b^2 + c^2x^2

du/dx = 2cx

By taking integration we get

∫ 3ax/(b^2 +c^2x^2) dx = (3a/c) ∫ du/u

Integration of ∫ du/u is ln|u| + C

∫ 3ax/(b^2 +c^2x^2) dx = (3a/c) ln|u| + C

By substituting value of given value of u,

∫ 3ax/(b^2 +c^2x^2) dx= (3a/c) ln|b^2 + c^2x^2| + C

By substituting back in terms of x, we get

∫ 3ax/(b^2 +c^2x^2) dx = (3a/c) ln|b^2 + c^2x^2| + C

Hence, The provided integral's answer is this.

For similar question on integration,

https://brainly.in/question/52368494

#SPJ3

Similar questions