Question

Evaluate: ∫ 3ax/(b2 +c2x2) dx

please give the right answer

Answer 1

Answer:

To evaluate the integral, I = ∫ 3ax/(b2 +c2x2) dx

Let us take v = b2 +c2x2, then

dv = 2c2x dx

Thus, ∫ 3ax/(b2 +c2x2) dx

= (3ax/2c2x)∫dv/v

Now, cancel x on both numerator and denominator, we get

= (3a/2c2)∫dv/v

= (3a/2c2) log |b2 +c2x2| + C

Where C is an arbitrary constant