evaluate 3b-2a and 2a+5b
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Answered by
1
Answer:
The given polynomials are 2a+3b and 2a−3b we multiply them as follows:
(2a+3b)(2a−3b)=(2a×2a)+(2a×−3b)+(3b×2a)+(3b×−3b)=4a
2
−6ab+6ab−9b
2
=4a
2
−9b
2
Hence, (2a+3b)(2a−3b)=4a
2
−9b
2
.
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Answered by
0
answer is 8b
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