Math, asked by kancharlameghana2223, 9 months ago

Evaluate 3cos 55°/7sin35° - 4(cos70°×cosec20°) / 7(tan25°×tan5°×tan45°×tan65°×tan25° )

Answers

Answered by spiderman2019
3

Answer:

-1/7

Step-by-step explanation:

cos55°=cos(90°-35°)=sin35°  

cos70°=cos(90°-20°)=sin20°  

tan5°= tan(90° - 85°) = cot85°

tan25°=tan(90° - 65°) = cot65

tan45°  = 1

3cos 55°/7sin35° - 4(cos70°×cosec20°) / 7(tan25°×tan5°×tan45°×tan65°×tan85° )

= 3sin35°/7sin35° - 4 (sin20*cosec20°) / 7 (cot65° × cot85° × tan45° × tan65° × tan85°)

= 3sin35°/7sin35° - 4 (sin20*cosec20°) / 7 (1/tan65° × 1/tan85° × tan45° × tan65° × tan85°)

= [3/7 - 4 /7]  

= -1/7

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