Evaluate: 3tan²30°+ tan²60°+cosec 30°-tan 45°/ cot²45°
(Class 10 Maths Sample Question Paper)
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Answered by
39
Solution:
3 tan² 30°+ tan² 60°+ cosec 30°- tan 45°/ cot² 45°
= 3 (1 /√3)² + (√3)² + 2-1 / (1)²
[tan 30° = 1/√3, tan 60°= √3, cosec 30°= 2, tan 45°= 1, cot 45°= 1]
= 3 × 1/3 + 3 +1 /1
= 1+ 4 /1
= 5 /1
= 5
HOPE THIS WILL HELP YOU...
3 tan² 30°+ tan² 60°+ cosec 30°- tan 45°/ cot² 45°
= 3 (1 /√3)² + (√3)² + 2-1 / (1)²
[tan 30° = 1/√3, tan 60°= √3, cosec 30°= 2, tan 45°= 1, cot 45°= 1]
= 3 × 1/3 + 3 +1 /1
= 1+ 4 /1
= 5 /1
= 5
HOPE THIS WILL HELP YOU...
Answered by
14
Heya friend,
Here is your answer,
The answer is 5.
Hope it helps you.
Thank you.
Here is your answer,
The answer is 5.
Hope it helps you.
Thank you.
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