Math, asked by anuj9863, 1 year ago

evaluate 3under root (343)^-2

Answers

Answered by Anonymous
10
Heya ✋

Let see your answer !!!!

 \sqrt[3]{343 ^{ - 2} }  \\  = (343) ^{ \frac{ - 2}{3} }  \\  = (7) ^{3 \times  \frac{ - 2}{3} }  \\  = (7) ^{ - 2}  \\  =  \frac{1}{7 ^{2} }  \\  =  \frac{1}{49}




Thanks :))))
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