evaluate (3x+5)3 (it's power to 3)....anyone please help
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apply the identity (a+b)^3= a^3+ b^3+3ab(a+b)
(3x+5)^3=(3x)^3+5^3+3×3x×5(3x+5)
=27x^3+125+45x(3x+5)
=27x^3+125+135x^2+225x
(3x+5)^3=(3x)^3+5^3+3×3x×5(3x+5)
=27x^3+125+45x(3x+5)
=27x^3+125+135x^2+225x
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here is your answer--
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anu161:
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