Math, asked by tahir8644, 11 months ago

Evaluate 3x²-2y³ when x = 2 and y = -1

Answers

Answered by mumtazkhan99
1

Ans

3x^2-2y^3,

but x=2and y=-1

3(2)^2-2(-1)^3=3×4-2×(-1)=12+2=14

Answered by harendrachoubay
5

If x = 2 and y = - 1, then 3x^2-2y^3 = 14

Step-by-step explanation:

We have,

3x^2-2y^3 , x = 2 and y = -1

To find, 3x^2-2y^3 = ?

3x^2-2y^3

Put x = 2 and y = - 1, we get

3(2)^2-2(-1)^3

=3(4)-2(-1)

=12+2

= 14

∴ If x = 2 and y = - 1, then 3x^2-2y^3 = 14

Hence, if x = 2 and y = - 1, then 3x^2-2y^3 = 14

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