Question

evaluate 3x³+2x²+x+¹for a) x=2b) x=-1c) x=0​

Answer 1

Answer:

a)

Step-by-step explanation:

$let \: f(x) = 3 {x}^{3} + 2 {x}^{2} + x + 1$

$f(2) = 3 ({2}^{3} ) + 2( {2}^{2} ) + 2 + 1$

f(2)= 3(8)+2(4)+2+1

f(2) = 24+8+2+1=35

to get f(-1) substitute x = -1

$f( - 1) = 3( { - 1}^{3} ) + 2( { - 1}^{2}) + ( - 1)+ 1$

f(-1)= 3(-1)+2(1)

f(-1) = -3+2= -1

to get f(0) substitute x=0

f(0) = 3(0)+2(0)+0+1 = 1

Answer 2

Answer:

sorry I don't know the answer

Step-by-step explanation:

I'm surching for that question