Question

evaluate (4^-1+8^-1)/(2/3)​

Answer 1

Answer:

$\frac{ {4}^{ - 1} + {8}^{ - 1} }{ \frac{2}{3} } \\ \\ \frac{ { \frac{4}{1} }^{1} + { \frac{8}{1} }^{1} }{ \frac{2}{3} } \\ \\ \frac{{( \frac{4}{1} + \frac{8}{1} )}^{1} }{ \frac{2}{3} } \\ \\ \frac{ { \frac{12}{1} }^{1} }{ \frac{2}{3} } \\ \\ \frac{12}{1} \times \frac{3}{2} \\ \\ \frac{6}{1} \times \frac{3}{1} \\ \\ \frac{18}{1} = 18$

I hope it may help you

Answer 2

Answer:

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