Math, asked by savithamanjunatha198, 2 months ago

evaluate (4^-²+3^-²)-² ×(6/25)-² ​

Answers

Answered by Anonymous
2

( { {4}^{ - 2}  +  {3}^{ - 2} })^{ - 2}  \times  ({ \frac{6}{25} })^{ - 2}  \\  \\  \implies \:  {( \frac{1}{ {4}^{2}  }  +  \frac{1}{ {3}^{2} } )}^{ - 2}  \times   ({ \frac{25}{6} })^{2}  \\  \\  \implies \: ( { \frac{1}{16}   +  \frac{1}{9} })^{ - 2}  \times  \frac{625}{36}  \\  \\  \implies \: ( { \frac{9 + 16}{144} })^{ - 2}  \times  \frac{625}{36}  \\  \\  \implies \: ( { \frac{25}{144} })^{ - 2}  \times  \frac{625}{36} \\  \\  \implies \: ( { \frac{144}{25} })^{ 2}   \times  \frac{625}{36}  \\  \\  \implies \: \:  \frac{144 \times  \cancel{144} \:  \: ⁴}{  \cancel{25} \times  \cancel{25}}  \times  \frac{ \cancel{625}}{ \cancel{36}}  \\  \\  \implies \: 576....

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