Math, asked by Afshy, 5 months ago

evaluate 4(a+b)square -20(a+b)+25 when a=2 b=1​

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Answered by Anonymous
0

a3 +b3 + a + b = 4 + 1 = 5

(a + b)(a2 - ab + b2) + (a +b) = 5

1(a2 - ab + b2) + 1 = 5

a2 - ab +b2 = 4 NOTE: b = (1 - a)

a2 - a(1-a) +(1 - a)2 = 4

a2 - a + a2 + 1 - 2a + a2 = 4

3a2 - 3a - 3 = 0 or a2 - a - 1 = 0

Similarly, if we set a = (b - 1), we get b2 - b - 1= 0

a2 - a - 1 + b2 - b -1 = 0

a2 + b2 - (a + b) - 2 = 0

a2 + b2 - 1 - 2 = 0

a2 + b2 = 3

A2

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