Question

Evaluate: 4 sin^2 60° + 3 tan^2 30° - 8 sin 45° cos 45°
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Answer 1

Step-by-step explanation:

4× √3/2^2 + 3×1/√3^2 - 8× 1/√2 ×1/√2 =

3+1-4=0

the answer is zero(0)

Answer 2

Answer:

4(Sin² 60°) + 3(Tan² 30°) - 8(Sin 45°)(Cos 45°) = 0

Step-by-step explanation:

We know that,

Sin 60° = √3/2

Tan 30° = 1/√3

Sin 45° = 1/√2

Cos 45° = 1/√2

So we have,

4(Sin² 60°) + 3(Tan² 30°) - 8(Sin 45°)(Cos 45°)

4(Sin 60°)² + 3(Tan 30°)² - 8(Sin 45°)(Cos 45°)

4(√3/2)² + 3(1/√3)² - 8(1/√2)(1/√2)

4(3/4) + 3(1/3) - 8(1/2)

3 + 1 - 4

4 - 4

0

Hence,

4(Sin² 60°) + 3(Tan² 30°) - 8(Sin 45°)(Cos 45°) = 0

Hope it helped and believing you understood it........All the best