Question

evaluate 4 tan square 45°-8cos square 60° plus sin square 60° plus cos square 90°​

Answer 1

Given:

4cot^245-sec^260+sin^260+cos^2904cot

2

45−sec

2

60+sin

2

60+cos

2

90

To find "

The value of given expression

Solution:

4cot^245-sec^260+sin^260+cos^2904cot

2

45−sec

2

60+sin

2

60+cos

2

90

We know that

cot45=1cot45=1

sec60=2sec60=2

sin60=\sqrt{3}/2sin60=

3

/2

cos90=0cos90=0

Substitute the values then, we get

=4-(2)^2+(\frac{\sqrt{3}}{2})^2+0=4−(2)

2

+(

2

3

)

2

+0

=4-4+\frac{3}{4}=4−4+

4

3

=\frac{3}{4}=

4

3

Hence,

4cot^245-sec^260+sin^260+cos^290=\frac{3}{4}4cot

2

45−sec

2

60+sin

2

60+cos

2

90=

Answer 2

Answer:

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Step-by-step explanation:

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