Question

Evaluate -4abc(6a²+2b²) when a =1, b=-1 ,c=5 ​

Answer 1

Answer:

Step-by-step explanation:

-4abc(6a²+2b²)

when a =1, b=-1 ,c=5 ​

-4abc(6a²+2b²)

=-4*1*-1*5(6*1²+2(-1)²)

=20(6+2)

=20*8

=160

Answer 2

Answer:

refer to the attachment hope it helps you g ❤️