Question

evaluate 4x^2 +y^2+9z^2-4xy+6yz-12zx using identity if x=3 , y=1 , z=2​

Answer 1

Answer:

397

Step-by-step explanation:

Answer 2

Answer:

1

Step-by-step explanation:

${(x + y + z)}^{2} = {x}^{2} + {y }^{2} + {z}^{2} + 2xy + 2xz + 2yz$

${( - 2x)}^{2} + {(y)}^{2} + {(3z)}^{2} + 2( - 2x)(y) + 2(y)(3z) + 2( - 2x)(3z)$

${( - 2x + y + 3z)}^{2}$

At x=3,y=1 and z=2

${{(( - 2)(3) + ( 1) + (3)(2))}}^{2}$

$( - 6 + 1 + 6)$

$1$

Therefore Answer is 1