Math, asked by mohinisingh7105, 6 months ago

Evaluate (5-¹×4-¹)×(3/2)-²​

Answers

Answered by Anonymous
17

Answer:

\sf{}\dfrac{1}{90}

Explanation:

\Rightarrow\sf{}(5^-1\times4^{-1})\times \bigg(\dfrac{3}{2}\bigg)^{-2}

\sf{}\Rightarrow\bigg(\dfrac{1}{5}\bigg) ^{1}\times\bigg(\dfrac{1}{4}\bigg) ^{1}\times\bigg(\dfrac{2}{3}\bigg) ^{2}

\sf{}\Rightarrow \dfrac{1}{5}\times \dfrac{1}{4}\times \dfrac{2}{9}

\Rightarrow \dfrac{2}{180}

\sf{}\Rightarrow \dfrac{1}{90}

\bigstar \sf{}Laws\ of\ exponent}\bigstar [For\ a\neq0,b\neq0]

1)a^x\times a^y=a^{x+y}

2)a^x\div a^y=a^{x-y}

3)(a^x)^y=a^{xy}

4)a^0=1

5)a^{-1}=\dfrac{1}{a}

6)\bf \sqrt[n]{ \sqrt[m]{ \sqrt[p]{((a^{x} )^{y}) ^{z}  } } }  = (a ^{xyz} )^{ \frac{1}{mnp} }  = a ^{ \frac{xyz}{mnp} }

Answered by Bᴇʏᴏɴᴅᴇʀ
3

Question:-

➣ Evaluate:-

Answer:-

 ({5}^{-1} × {4}^{-1})× (\frac{3}{2})^{-2}

Solution:-

({5}^{-1} × {4}^{-1}) ×  (\dfrac{3}{2})^{-2}

(\dfrac{1}{5}) ^{1}\times(\dfrac{1}{4}) ^{1}\times(\dfrac{2}{3}) ^{2}

\dfrac{1}{5}\times \dfrac{1}{4}\times \dfrac{2}{9}

\dfrac{2}{180}

\cancel{\dfrac{2}{180}}

\dfrac{1}{90}

\huge{\purple{\dfrac{1}{90}}}

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