Math, asked by meny, 11 months ago

Evaluate: (5^-1 * 8^2)/(2^-3*10^-1)

Answers

Answered by DaIncredible
37

Answer:

 \bf  {2}^{10}

Step-by-step explanation:

 \frac{ {5}^{ - 1} \times  {8}^{2}  }{ {2}^{ - 3} \times  {10}^{ - 1}  }  \\  \\  =  \frac{ {8}^{2} \times  {2}^{3}  \times  10  }{5}  \\  \\  =  {( {2}^{3} )}^{2}   \times   {2}^{3}   \times  2 \\  \\  =  {2}^{6}   \times  {2}^{3}  \times 2 \\  \\  =  {2}^{6 + 3 + 1}  \\  \\  \bf =  {2}^{10}

Answered by nikunjdeshwal25
6

1024

Step-by-step explanation:

(5^-1 * 8^2 ) ÷ ( 2^-3 * 10 ^ -1 l

(1/5 * 64 ) ÷ ( 1/8 * 1/10 )

64/5 ÷ 1/ 80

64/5 × 80

64 × 16 { 80 / 5 = 16 }

= 1024

HOPE IT HELPED.

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