Evaluate
-5/3 a^2 + 3/4 a b c + 5 at a=(-2), b=1, c=2
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Answer:
We have,
a
1
+
b
1
+
c
1
=1 and abc=2
abc
bc+ca+ab
=1
bc+ca+ab=abc
On multiply by abc both sides, we get
abc(bc+ca+ab)=abc×abc
ab
2
c
2
+a
2
bc
2
+a
2
b
2
c=(abc)
2
ab
2
c
2
+a
2
bc
2
+a
2
b
2
c=2
2
=4
Hence, this is the answer.
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