Question

Evaluate (5 cos square 60 degree+ 4 sec square 30 degree- tan square 45 degree/ sin square 30 degree+ cos square 30 degree)+ cos square 90 degree

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

$Value \:of \:\frac{(5cos^{2}60+4sec^{2}30-tan^{2}45)}{(sin^{2}30+cos^{2}30)}+cos^{2}90=\frac{67}{12}$

Step-by-step explanation:

$\frac{(5cos^{2}60+4sec^{2}30-tan^{2}45)}{(sin^{2}30+cos^{2}30)}+cos^{2}90$

$=\frac{5\times \left(\frac{1}{2}\right)^{2}+4\times \left(\frac{2}{\sqrt{3}}\right)^{2} - 1}{1}+0$

$=\frac{5\times \left(\frac{1}{4}\right)+4\times \left(\frac{4}{3}\right) - 1}{1}$

$=\frac{5}{4}+\frac{16}{3}-1\\=\frac{15+64-12}{12}\\=\frac{67}{12}$

Therefore,

$Value \:of \:\frac{(5cos^{2}60+4sec^{2}30-tan^{2}45)}{(sin^{2}30+cos^{2}30)}+cos^{2}90=\frac{67}{12}$

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