evaluate: 5 cos²60°+4 sec²30°-tan²45° ÷ sin²30° +cos²30°
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( 5 cos²60°+4 sec²30°-tan²45°) ÷ (sin²30° +cos²30°)
= {5*(1/2)^2+ 4 (√3/2)^2-(1)^2}
÷{ (1/2)^2+(√3/2)^2}
={ 5/4+4*(3/4)-1}÷ (1/4+3/4)
= 5/4-2 ÷ 1
= -3/2
khanujarashmit:
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change sec into sin and tan into sin and cos and apply the identity.
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