Question

evaluate 5 root 3 + 4 root 27 + 2 upon under root 3​

Answer 1

Answer:

5√3 +4√27+2÷√3

=(5√9+4√81+2√3)÷√3 [Making the denominator common by multiplying with√3]

=(5×3+4×9+2√3)÷√3 [Because√9=3 and √81=9]

=(15+36+2√3)÷√3

=(51+2√3)÷√3

=【(51+2√3) × (√3)】÷3 [ Rationalizing the denominator by multiplying and dividing by√3]

=(51√3+2×3) ÷3 [Because √3 × √3=3]

=(51√3+6)÷3

=【3(17√3+2)】÷3 [Taking 3 common from the denominator]

=17√3+2 [Cancelling 3 from the numerator and denominator]