Math, asked by raktechs75, 7 months ago

Evaluate (501)3 using suitable identity.

Answers

Answered by Ayushkumarchaudhary
3

Answer:

(500+1)

x+y³=x³+y³+3xy+(x+a)

500³+1³+3×500×1+(500+1)

125000000+1+1501+(500+1)

125000000+750500+1501+1

125752002

Answered by brainhunter16
12

Answer:

125751501

Step-by-step explanation:

We can solve this by using this identity:

(a+b)³ = a³+b³+3ab(a+b)

= (501)³

= (500+1)³

= (500)³+(1)³+3×500×1(500+1)

= 125000000+1+1500×501

= 125751501

Hope it helps you ^_^

Pls mark my answer as brainliest and follow me. ^_^

Similar questions