Evaluate 5a^2 + 2b^3 when a=4 and b =-4
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5a²+2b³
5(4)²+2(-4)³
5×16+2×(-64)
80-128=-48
5(4)²+2(-4)³
5×16+2×(-64)
80-128=-48
Answered by
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Hello there! How are you today?
5a^2 + 2b^3, solve when a = 4 and b = -4
To solve for this, we must replace "a" with 4, and "b" with -4.
I will set it up;
5(4^2) + 2(-4^3)
Simplify the parenthesis (PEMDAS).
5(16) + 2(-64)
Remove the parenthesis by multiplying them by the numbers to the outside of them.5 x 16 = 80
2 x -64 = -128
We are now left with:
80 - 128
Simplify.
-48 is your final answer.
I hope this helps
-Ekansh Nimbalkar
5a^2 + 2b^3, solve when a = 4 and b = -4
To solve for this, we must replace "a" with 4, and "b" with -4.
I will set it up;
5(4^2) + 2(-4^3)
Simplify the parenthesis (PEMDAS).
5(16) + 2(-64)
Remove the parenthesis by multiplying them by the numbers to the outside of them.5 x 16 = 80
2 x -64 = -128
We are now left with:
80 - 128
Simplify.
-48 is your final answer.
I hope this helps
-Ekansh Nimbalkar
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