Question

Evaluate 5cos^260°+4cos^230°-tan^245/sin^230°+cos^260°

Answer 1

hey mate,...

here's your answer,...

$5 { \cos(60) }^{2} = \frac{5}{4} \\ 4 { \cos(60) }^{2} = 3 \\ { \tan(45) }^{2} = \frac{1}{2} \\ { \sin(30) }^{2} = \frac{1}{4} \\ { \cos(60) }^{2} = \frac{1}{4} \\ \frac{ {5 \cos(60) }^{2} + {4 \cos(30) }^{2} - { \tan(45) }^{2} }{ { \sin(30) }^{2} + { \cos(60) }^{2} } = \frac{5}{4} + 3 - \frac{1}{2} \div \frac{1}{4} + \frac{1}{4} = \\ \frac{15}{2} = 7.5$

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