Question

evaluate:5sin²30degree+cos²45degree-4tan²30degree/2sin30 degreecos30degree+tan 45 degree

Answer 1

5×(1/2)²+(1/√2)²-4(1/√3)³÷(2×1/2×√3/2+1)
(5/4+1/2-4/3√3)/(√3/2+1)

=
(15√3+6√3-16)/12√3÷(√3+2)/2
(21√3-16)×2/(12√3×√3+2)

=
42√3-32)/(36+24√3)