Question

evaluate 6 upon root 12-root 3​

Answer 1

Answer:

Step-by-step explanation:

$\frac{6}{\sqrt{12}} - \sqrt{3}$

= $\frac{6 - \sqrt{3} *\sqrt{12} }{\sqrt{12}}$  ( taking LCM)

= $\frac{6 -\sqrt{36} }{12}$

= $\frac{6 - 6}{\sqrt{12}}$

= $\frac{0}{\sqrt{12} }$

= 0

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$\frac{6}{\sqrt{12}} - \sqrt{3}$

= $\frac{6}{\sqrt{4*3}} - \sqrt{3}$

= $\frac{6}{2\sqrt{3}} - \sqrt{3}$

= $\frac{3}{\sqrt{3}} - \sqrt{3}$

= $\frac{3 - 3 }{\sqrt{3}}$

= $\frac{0}\sqrt{3} {}$

= 0