Math, asked by rupalalan1982, 1 month ago

evaluate (6° + 15') × (12° + 5)​

Answers

Answered by Anonymous
0

∆ Solution

( {6}^{0}  +  {15}^{1} ) \times ( {12}^{0}  + 5) \\ 0 + 15 \times 0 + 5 \\ 15 + 5 \\  = 20

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