Question

. Evaluate
6cos60° - Sin30° + Sin 45º + cos245°​

Answer 1

as we know that:-

cos60=1/2

sin30=1/2

sin45=1/√2

cos90=0

so substituting these values we get

6×1/2-1/2+1/√2+0

3-1/2+1/√2=5√2+2/2√2

Answer 2

Answer:

The answer is : $3-1/2+1/\sqrt{2} =5\sqrt{2} +2/2\sqrt{2}$

Step-by-step explanation:

Sine and cosine—aka, sin(θ) and cos(θ)—are functions that reveal the shape of a right triangle. When viewed from the vertex with angle θ, sin(θ) is the ratio of the opposite side to the hypotenuse, while cos(θ) is the ratio of the adjacent side to the hypotenuse. Regardless of the size of the triangle, the values ​​of sin(θ) and cos(θ) are the same for a given θ

The sine function is one of the three primary functions in trigonometry, the others being the cosine and tan functions.

In trigonometry, the sine function can be defined as the ratio of the length of the opposite side to the length of the hypotenuse in a right triangle. The sine function is used to find the unknown angle or sides of a right triangle.

For any right triangle, say ABC, with angle α, the sine function will be:

Sin α= opposite/hypothesis

As we know, the sine function is defined for all real numbers, so the domain of y = sin x is the set of all real numbers, i.e. R. The domain of the sine function is the closed interval [-1, 1]. That is, -1 ≤ y ≤ 1 or -1 ≤ sin x ≤ 1. However, the range of this function can be given by quadrants.

As we know that:-

cos60°=1/2

sin30°=1/2

sin45°=$1/\sqrt{2}$

cos90°=0

so substituting these values we get

$6*1/2-1/2+1/\sqrt{2} +0$

$3-1/2+1/\sqrt{2} =5\sqrt{2} +2/2\sqrt{2}$

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