Math, asked by nabe075177, 4 months ago

Evaluate 6x² -2y² for x= 3 and y=1

Answers

Answered by AbhinavRocks10
2

Step-by-step explanation:

4xy(x−y)−6x

4xy(x−y)−6x 2

4xy(x−y)−6x 2 (y−y

4xy(x−y)−6x 2 (y−y 2

4xy(x−y)−6x 2 (y−y 2 )−3y

4xy(x−y)−6x 2 (y−y 2 )−3y 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2 +2x

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2 +2x 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2 +2x 2 y−2xy

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2 +2x 2 y−2xy 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2 +2x 2 y−2xy 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2 +2x 2 y−2xy 2 =6x

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2 +2x 2 y−2xy 2 =6x 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2 +2x 2 y−2xy 2 =6x 2 y−6xy

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2 +2x 2 y−2xy 2 =6x 2 y−6xy 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2 +2x 2 y−2xy 2 =6x 2 y−6xy 2 −6x

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2 +2x 2 y−2xy 2 =6x 2 y−6xy 2 −6x 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2 +2x 2 y−2xy 2 =6x 2 y−6xy 2 −6x 2 y+3xy

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2 +2x 2 y−2xy 2 =6x 2 y−6xy 2 −6x 2 y+3xy 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2 +2x 2 y−2xy 2 =6x 2 y−6xy 2 −6x 2 y+3xy 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2 +2x 2 y−2xy 2 =6x 2 y−6xy 2 −6x 2 y+3xy 2 =−3xy

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2 +2x 2 y−2xy 2 =6x 2 y−6xy 2 −6x 2 y+3xy 2 =−3xy 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2 +2x 2 y−2xy 2 =6x 2 y−6xy 2 −6x 2 y+3xy 2 =−3xy 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2 +2x 2 y−2xy 2 =6x 2 y−6xy 2 −6x 2 y+3xy 2 =−3xy 2 =−3(5)(13)

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2 +2x 2 y−2xy 2 =6x 2 y−6xy 2 −6x 2 y+3xy 2 =−3xy 2 =−3(5)(13) 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2 +2x 2 y−2xy 2 =6x 2 y−6xy 2 −6x 2 y+3xy 2 =−3xy 2 =−3(5)(13) 2

4xy(x−y)−6x 2 (y−y 2 )−3y 2 (2x 2 −x)+2xy(x−y)=4x 2 y−4xy 2 −6x 2 y+6x 2 y 2 −6x 2 y 2 +3xy 2 +2x 2 y−2xy 2 =6x 2 y−6xy 2 −6x 2 y+3xy 2 =−3xy 2 =−3(5)(13) 2 =−2535

Answered by nandanaMK
7

 \sf \huge\red{\underline{ \underline{Answer :}}}

 \\  \\  \\  \\  \large \tt6 {x}^{2}  - 2 {y}^{2}  \\   \\ \tt{x = 3 \:  \:  \:  \: y = 1} \\  \\   \large\tt6 {(3)}^{2}  - 2 {(1)}^{2}  \\  \\  \large\tt 6(9) - 2(1) \\  \\  \large\tt 54 - 2 \\  \\ \underline{\underline{ \large \tt  \:  \: 52 \:  \: }}

 \\  \\  \\  \\  \\  \color{purple}{ \bf{Hope \:   \: this \:   \: helps  \: \:  you \: !}}

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