Question

Evaluate: (7^-1+8^-1 +9^-1)^0

÷ (-1/9) ^-2​

Answer 1

Any number raised to 0 is 1 [a^0=1]

Therefore, (7^-1+8^-1+9^-1)^0 = 1

(-1/9)^-2 = 1/81

So, 1/(-1/9)^-2 = 1/(1/81)

                      = 81

Answer 2

Answer:

1/81

Step-by-step explanation:

$(7^{-1} +8^{-1}+9^{-1} )^0$/$(-1/9)^{-2}$                          

when powers are in negative reciprocal the given number

$(1/7+1/8+1/9)^0/(-9)^2$        

$(72+63+56/504)^0$/$(-9)^2$

$(161/504)^0/(-9)^2$

anything raise to power 0 =1

$1/(-9)^2$                                                    (- * - = +)

1/81