Math, asked by saisakshirajput, 8 days ago

evaluate 7(a square-b square) cube+7(b square-c square) cube +7( c square-a square) cube by (a-b) cube+(b-c) cube+(c-a) cube​

Answers

Answered by llItzDishantll
55

Solution:

 

/* we know that,  

if x+y+z = 0 then x³+y³+z³ = 3xyz */  

i) [(a²-b²)³+(b²-c²)³+(c²-a²)]/[(a-b)³+(b-c)³+(c-a)³]  

= [3(a²-b²)(b²-c²)(c²-a²)]/[3(a-b)(b-c)(c-a)]  

=[(a+b)(a-b)(b+c)(b-c)(c+a)(c-a)]/[(a-b)(b-c)(c-a)]  

After cancellation,we get  

= (a+b)(b+c)(c+a)  

••••

Answered by itztaesprincessliza
0

Answer:

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