evaluate 71 using the identity ''(a+b)2 ==a2+b2+2ab"
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✔✔ Answer ✔✔
☁ (70 + 1)^2 ☁
✏ (70)^2 + (1)^2 + 2(70)(1)
✏ 4900 + 1 + 140
✏ 5041
☁ (70 + 1)^2 ☁
✏ (70)^2 + (1)^2 + 2(70)(1)
✏ 4900 + 1 + 140
✏ 5041
Answered by
2
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lloyd4117:
thnx
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