Math, asked by valsapoulosealuva, 4 months ago

evaluate(7x_3y)( 5x-2y)​

Answers

Answered by 11177420
1

\red{\boxed{\boxed{  {35x}^{2}  - 29xy +  {6y}^{2} }}}

Step-by-step explanation:

 = (7x - 3y)(5x - 2y)

 = (7x \times 5x) - (7x \times 2y) - (3y \times 5x)  +  (3y \times 2y)

 =  {35x}^{2}   - 14xy - 15xy+  {6y}^{2}

 =  {35x}^{2}  - 29xy +  {6y}^{2}

{\purple{\boxed{ {\mathfrak{\underline{\purple{ @11177420 }}}} }}}

Answered by Fadhilla
0

Answer:

35x^2 - 29xy + 6y^2

Step-by-step explanation:

evaluate(7x_3y)( 5x-2y)

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