Math, asked by valsapoulosealuva, 3 months ago

evaluate(7x_3y)( 5x-2y)​

Answers

Answered by 11177420
2

\red{\boxed{\boxed{  {35x}^{2}  - 29xy +  {6y}^{2} }}}

Step-by-step explanation:

 = (7x - 3y)(5x - 2y)

 = (7x \times 5x) - (7x \times 2y) - (3y \times 5x)  +  (3y \times 2y)

 =  {35x}^{2}   - 14xy - 15xy+  {6y}^{2}

 =  {35x}^{2}  - 29xy +  {6y}^{2}

{\purple{\boxed{ {\mathfrak{\underline{\purple{ @11177420 }}}} }}}

Answered by TJain9
1

Answer:

Step-by-step explanation:

(7x - 3y)(5x-2y)​\\(35x^{2} -14xy) (15xy + 6y^{2})\\35x^{2} +xy +6y^{2}

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