Question

Evaluate (8^(-1)×5^3)/(2^(-4)).

Answer 1

Hey buddy, here is your answer.

On evaluating, the final outcome is= 250

As
$\frac{ {8}^{ - 1} \times {5}^{3} }{ {2}^{ - 4} }$
So on changing the position of values, we get
$\frac{ {2}^{4} \times {5}^{3} }{ {8}^{1} }$
i.e.
$\frac{16 \times 125}{8}$
which is equal to 250

Hope it helps you.
Plz mark me as brainliest.

Answer 2

$\huge\mathcal{Answer \ :-}$

$\mathsf{Given \ :-}$

$\frac{ {8}^{ - 1} \times {5}^{3} }{ {2}^{ - 4} } \\ \\ = > \frac{ ({ {2}^{3} )}^{ - 1} \times {5}^{3} }{ {2}^{ - 4} } \\ \\ = > \frac{ {2}^{ - 3} \times {5}^{3} }{ {2}^{ - 4} } \\ \\ = > {2}^{ - 3 - ( - 4)} \times {5}^{3} \\ \\ = > {2}^{ - 3 + 4} \times {5}^{3} \\ \\ = > {2}^{1} \times {5}^{3} \\ \\ = > 2 \times 125 \\ \\ = > 250$

$\huge\mathbb{Hope \ this \ helps.}$