evaluate : [8+{6×2-(1+8÷2)+1}
Answers
Answered by
2
We have ,
[8+{6×2-(1+8÷2)+1}
= [8+{6×2-(1+4)+1}]
= [8+{6×2-5+1}]
= [8+{12-5+1}]
= [8+{12-4}]
= [8+8]
= 16
Hope it helps you , plz mark me as brainliest
Similar questions