Math, asked by ArpitAgrawal, 1 year ago

evaluate (8/9)^3/2×(8)^1/3​

Answers

Answered by Anonymous
5

Given:

 { (\frac{8}{9}) }^{ \frac{3}{2} }  \times  {(8)}^{ \frac{1}{3} }

But,

8 =  {2}^{3} and \: 9 =  {3}^{2}

Putting the respective values, we get,

 =    {(\frac{ {2}^{3} }{ {3}^{2} }) }^{ \frac{3}{2} }  \times  {( {2}^{3}) }^{ \frac{1}{3} }

Now, we know that,

 {( \frac{ {a}^{m} }{ {b}^{n} } )}^{x}  =  \frac{ {a}^{mx} }{ {b}^{nx} }

So, according to this, we get,

 =  \frac{ {2}^{ \frac{9}{2} } }{ {3}^{3} }   \times  {2}^{1}

Now,we know that,

 {a}^{m}  \times  {a}^{n }  =  {a}^{(m + n)}

so, according to this, we get,

 =  \frac{ {2}^{ (\frac{9}{2}  + 1) } }{ {3}^{3} }

 =  \frac{ {2}^{ \frac{11}{2} } }{  {3}^{3} }

 =  \frac{ {2}^{5}   \times  {2}^{ \frac{1}{2} }  }{ {3}^{3} }

 =  \frac{32 \sqrt{2} }{27}


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