Math, asked by Aditya26808, 9 months ago

evaluate (81)-¹×3-⁵×3⁹×(64)⅚×(³√³)⁶

Answers

Answered by mysticd
11

 (81)^{-1} \times (3)^{-5} \times 3^{9} \times (64)^{\frac{5}{6}} \times \Big( \sqrt[3] {3}\Big)^{6}

 = (3^{4})^{-1} \times (3)^{-5} \times 3^{9} \times (2^{6})^{\frac{5}{6}} \times (3)^{\frac{6}{3}}

 = 3^{-4} \times (3)^{-5} \times 3^{9} \times (2)^{6 \times \frac{5}{6}} \times 3^{2}

 = 3^{-4} \times (3)^{-5} \times 3^{9} \times 2^{5} \times 3^{2}

 = 3^{-4-5+9+2} \times 2^{5}

/* By Exponential Law */

 \boxed {\pink{ a^{m} \times a^{n} = a^{ m + n }}}

 = 3^{2} \times 2^{5}

 = 9 \times 32

 = 288

Therefore.

 \red{(81)^{-1} \times (3)^{-5} \times 3^{9} \times (64)^{\frac{5}{6}} \times \Big( \sqrt[3] {3}\Big)^{6}}

 \green {= 288}

•••♪

Answered by 781456sukhman
1

Step-by-step explanation:

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