evaluate (81)¾×(243)⅘
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[81\(^{\frac{-3}{4}}\) x 25\(^{\frac{1}{2}}\) x 243\(^{\frac{2}{5}}\)
= [\((\sqrt[4]{81})^{-3} \times \sqrt{25} \times (\sqrt[5]{243})^2\)]
= [\(\frac{5 \times 3^2}{3^{3}}\)]
= [\(\frac{5}{3}\)]
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