Math, asked by mpsmahendra7, 10 months ago

evaluate (-8x^2y^6)×(-20xy) for x=2.5 and y=1​

Answers

Answered by GarvTheGamer
9

Answer:

= -8 × – 20 × x2 × x × y6 × y

= 160x2+1 y6+1 = 160x3y7

Now let us substitute when, x = 2.5 and y = 1

= 160x3y7 = 160 × (2.5)3 × (1)7

= 2500

Step-by-step explanation:

Answered by cosmiccreed
2

Answer:

HEY MATE HERE IS YOU ANSWER

Step-by-step explanation:

Let us simplify the given expression

=-8×–20×x2×x×y6×y=160x2+1 y6+1=160x3y7

Now let us substitute when, x = 2.5

and

y=1 =160x3y7=160×(2.5)3×(1)7=2500

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