evaluate 8x³+27y³ if 2x+3y=21/2 and xy=5/6
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Given,
2x+3y = 21/2
xy = 5/6
(2x+3y) ³ = 8x³ + 27y³ +18xy (2x+3y)
(21/2)³ = 8x³+27y³ + 18 (5/6) (21/2)
9261/8 = 8x³+27y³+315/2
8x³+27y³ = (9261/8) -315/2
8x³+27y³ = (9261 - 1260)/ 8
= 8001/8
Hope it will help you
2x+3y = 21/2
xy = 5/6
(2x+3y) ³ = 8x³ + 27y³ +18xy (2x+3y)
(21/2)³ = 8x³+27y³ + 18 (5/6) (21/2)
9261/8 = 8x³+27y³+315/2
8x³+27y³ = (9261/8) -315/2
8x³+27y³ = (9261 - 1260)/ 8
= 8001/8
Hope it will help you
anshu251:
nice try dear but the answer is 8001/8
Please check
It think this is right
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