evaluate (9.8)^3 by sutable ident
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Answer:
- We can write (9.8) as (9.0) &(0.8)
so, (9.8)=(9.0)+(0.8)
- We can substitute this in identity VI and can conclude that...
→(9.0+0.8)³
=(9.0)³+3(9.0)²(0.8)+3(9.0)(0.8)²+(0.8)³
=729+3(81)(0.8)+3(9.0)(0.64)+0.512
=941.192//
hope it's helpful.....
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