Math, asked by siddhardhreddy188, 2 months ago

Evaluate 9 sec2A – 9 tan2 A​

Answers

Answered by vidhiPokharna
1

Answer:

9

Step-by-step explanation:

We have,  9sec2A−9tan2A

Let  r=9sec2A−9tan2A

r=9(sec2A−tan2A)

We know that

sec2A−tan2A=1

Therefore,

r=9×1=9

Hence, this is the answer.

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Answered by IMsoumo
0

Answer:

Hence, this is the answer

Step-by-step explanation:

We have,  9sec2 A−9tan2 A

Let  r=9sec 2 A−9tan 2 A

r=9(sec2 A−tan2 A)

We know that  sec  2 A−tan 2 A=1

Therefore,

r=9×1=9

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