Math, asked by sarthak682, 9 months ago

Evaluate 99^2 by using the identity a^2+b^2=(a+b)(a-b).
plzz help me.....​

Answers

Answered by aryan073
2

Step-by-step explanation:

99²=9801

(99²+0²)=(99+0)(99-0)

=9801

Answered by rk4846336
2

Step-by-step explanation:

99^2 = (100 - 1)^2

= 1002 + 12 - 2×1×100

{(x-a)2 = x^2+a^2-2ax }

= 100×100 + 1×1 - 200

= 10000 + 1 - 200

= 10001 - 200

= 9801

So, 992 = 9801

mark it brainliest answer

have a nice day

Similar questions