Question

Evaluate (99)2 using Identity-II.
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Answer 1

${(99)}^{2} = {(100 - 1)}^{2}$

${(a - b)}^{2} = {a}^{2} + {b}^{2} - 2ab$

${100}^{2} + {1}^{2} - 2 \times 100 \times 1$

$10000 + 1 - 200$

$= 9801$