Evaluate (99)^2 using its identites
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Answered by
16
( 99 )²
=> ( 100 - 1 )²
=> ( 100 )² + ( 1 )² - 2( 100 × 1 )
=> 10000 + 1 - 200
=> 10000 - 199
=> 9801
=> ( 100 - 1 )²
=> ( 100 )² + ( 1 )² - 2( 100 × 1 )
=> 10000 + 1 - 200
=> 10000 - 199
=> 9801
Answered by
7
hey there!!
We can write this equation as
( 100 - 1 )^2
The identity of ( a - b )^2
= a^2 - 2ab + b^2
If we substitute, we get,
= 10000 - 200 + 1
= 9800 + 1
= 9801
hope my answer helps!! : )
We can write this equation as
( 100 - 1 )^2
The identity of ( a - b )^2
= a^2 - 2ab + b^2
If we substitute, we get,
= 10000 - 200 + 1
= 9800 + 1
= 9801
hope my answer helps!! : )
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