Math, asked by tanisha7528, 1 year ago

Evaluate (998)^3 using suitable identites.

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(998)^3

(1000-2)^3

[ (x-y)^3 = x^3 - y^3 - 3xy(x-y) ]

(1000)^3 - (2)^3 - 3×1000×2(1000-2)

1000000000 - 8 - 6000 (998)

1000000000 - 8 - 5,988,000

1000000000 - 5,988,008

= 994,011,992
Hope it help

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Answered by vyomgupta

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Answered by arunkumar33

(998)³=(1000-2)³

which gives

(a-b)³

(a-b)³=a³-b³-3ab(a-b)

=1000³-2³-3*1000*2(1000-2)

=1000000000-8-6000(998)

=1000000000-8-5988000

=1000000000-5988008

=994011992

therefore

(998)³=994011992

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Evaluate (998)^3 using suitable identites.