Math, asked by sindhugujjar534, 2 months ago

evaluate 999^2 by using the identity (a-b)^2 - 2ab + b^2

Answers

Answered by UmaDey

2

Step-by-step explanation:

999²

= (1000-1)²

= (1000)² - 2×1000×1 + (1)²

= 1000000 - 2000 + 1

= 998000 + 1

= 998001

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