Question

evaluate 999^2 using identities

Answer 1

999^2

(1000 - 1)^2

Using identity, (a - b)^2 = a^2 + b^2 -2ab

(1000 - 1)^2

(1000)^2 + (1)^2 - 2(1000×1)

1000000 + 1 - 2000

1000001 - 2000


998001





$.$


I hope this will help you

(-:

Answer 2

(1000-1)^2
=(1000)^2 + (1)^2 - 2(1000)(1)
=1000000+1-2000
=1000001-2000
=998001 Ans